Question

prove that 6 +√3

is irrational​

Answer 1

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Hey there,

let 6+√3 be a rational no.

6+√3 = a / b         [where a and b are co prime nos]

√3 = a / b - 6

√3 = a-6b / b

∴ a-6b / b is a rational no

   √3 is also a rational no

our assumption is wrong as contradiction fact says that √3 is not a rational no. 

∴ 6+√3 is an irrational no..

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