prove that 6 +√3
is irrational
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2
Hey there,
let 6+√3 be a rational no.
6+√3 = a / b [where a and b are co prime nos]
√3 = a / b - 6
√3 = a-6b / b
∴ a-6b / b is a rational no
√3 is also a rational no
our assumption is wrong as contradiction fact says that √3 is not a rational no.
∴ 6+√3 is an irrational no..
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