Question

prove that 6 - 4 under root 3 is an irrational number​

Answer 1

Let assume 6-4 root 3 is rational

6-4in root 3=a/b b not=0

-4in root3=a/b-6

-4root 3=a/b - 6/1

Root3=a-6b/-4b

Our assumption is wrong 6-4root 3 is irrational