Prove that 6-5√7 is an irrational number
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first we will prove that root 7 is irrational number
let root 7 is irrational number
so we can write it in the form of p by q where Q is not equal to zero
root 7 equals to P by q let P and Q as coprime number
so, 7p=q
it contradicts because we have let that p and q are coprime number but it has another factor except one so are assumption on is wrong .
root 7 is irrational
if use any operation with any rational number answer will always be irrational so 6 minus 5 root 7 is also a irrational hence proved
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