Question

prove that 6√5 are irrational number​

Answer 1

let us assume 6√5 as rational

6√5 = p/q ( p,q belongs to integers q not equalt to 0 hcf of p,q = 1)

√5 =p/6q

here lhs √5 is irrational but rhs p/6q is rational since p,q,6 are integers

there fore lhs not equal to rhs

this contradiction occured bcz we have assumed 6√5 as rational

our assumption is false

6√5 is a rational number.....

hence proved

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