Prove that 6 divides n(n + 1) (2n + 1) where n is any positive integer.
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Answers
Answer:
Let's start
We have, n(n+1)(2n+1)
Multipling the expression by 4 we have
4(n)(n+1)(2n+1) => 2(n)2(n+1)(2n+1)
Or, 2n(2n+2)(2n+1) => 2n(2n+1)(2n+2)
As we can see they were being three consecutive Number,therefore divisible by 3! But as first one is divisible by 2 and also the last one therefore for one of them is also divisible by 4
So the product is divisible by 24 and the original number i.e n(n+1)(2n+1) which was multiplied by 4 now can reduced by dividing the last expression but we now able to show that it is divisible by 24/4=6 so n(n+1)(2n+1) is divisible by 6
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Answer:
we can take n =2
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