Question

Prove that /6 is irrational.​

Answer 1

Answer:

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Answer 2

Let √6 be a rational no.

a/b = √6 , where a and b are co prime no.s

a = √6b ------(1)

a2 = 6b2 ( its a square equal to 6 b square )

( if p divisible by a then p is also divisible by a square )

let a = 6c

a2 = 6b2 then

(6c)2 = 6b2

36c square = 6 b square

6 c2 = b2

6c = b ------(2)

from (1) and (2)

it contradicts the fact that a and b are co prime no.s

therefore our assumption is wrong and √6 is an irrational no.

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