prove that √6 is irrational?
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Hey!!!
let's assume that root 6 is rational,
then, we have a/b , where a and b are co primes,
so, root 6 = a/b......(1)
root 6/b = a
as root 6 , a and b are rational nos
then Equation 1 is rational no
but, it contradicts the fact that root 6 is irrational no
Therefore our assumption is wrong
hence, root 6 is a irrational number.
hope it helps
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let's assume that root 6 is rational,
then, we have a/b , where a and b are co primes,
so, root 6 = a/b......(1)
root 6/b = a
as root 6 , a and b are rational nos
then Equation 1 is rational no
but, it contradicts the fact that root 6 is irrational no
Therefore our assumption is wrong
hence, root 6 is a irrational number.
hope it helps
mark it as brainliest
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