Question

prove that 6 n + 13 is and Odd integer Where n is an integer​

Answer 1

Answer:

6n + 13 is odd integer , n ∈ I. Case I : When n is an odd integer n = 2m + 1 ⇒ 6n + 13 = 6 (2m + 1) + 13 = 12 m + 6 + 13 Which is odd. Case II : When n = Even = 2m 6n + 13 = 6 (2m) + 13 = 12m + 13 Which is again odd.Read more on Sarthaks.com - https://www.sarthaks.com/341229/prove-that-6n-13-is-an-odd-integer-where-n-is-an-integer

Step-by-step explanation:

Answer 2

Answer: To prove : 6n + 13 is odd integer , n ∈ I. Case I : When n is an odd integer n = 2m + 1 ⇒ 6n + 13 = 6 (2m + 1) + 13 = 12 m + 6 + 13 Which is odd. Case II : When n = Even = 2m 6n + 13 = 6 (2m) + 13 = 12m + 13 Which is again odd.Read more on Sarthaks.com - https://www.sarthaks.com/341229/prove-that-6n-13-is-an-odd-integer-where-n-is-an-integer