Question

prove that (6)n cannot end with digit 0 or any natural no. n

Answer 1

hope it helps you
happy to help.....
please mark it as BRAINLIEST.......

Answer 2

Answer:

Step-by-step explanation:

(6)^n = (3×3)^n. Therefore, prime factorisation of 6^n does not contain 5 as a factor. Hence, 6^ n can never end with the digit 0 for any natural number