Math, asked by 9756845616, 1 year ago

prove that (6)n cannot end with digit 0 or any natural no. n

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Answered by poojavenkatesan
1
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Answered by rameshnenthra
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Answer:

Step-by-step explanation:

(6)^n = (3×3)^n. Therefore, prime factorisation of 6^n does not contain 5 as a factor. Hence, 6^ n can never end with the digit 0 for any natural number

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