Question

Prove that 6^n cannot end with the digit zero for any natural number n.
Plese explain the answer..​

Answer 1

Answer:

Hi

Step-by-step explanation:

If any number ends with the digit 0,it should be divisible by 10.

In other words,it will also be divisible by 2 and 5 as 10=2×5

Prime factorisation of 6^n=(2×3)^n

It can be observed that 5 is not in the primefactorisation of 6^n.

              Please mark it as a brainlist answer

Answer 2

Answer:

The prime factorsation of 6 can be written as 2×3

Step-by-step explanation:

If any number ends with 0 it should be divisible by 10 ,

as the prime factorsation of 6 is 2×3 here we can observe that 5 is not in the prime factorsation 6^

Hence , for any value of n, 6^ will not be divisible by 5

6^ cannot end with the digit zero for any natural number n

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