Question

prove that 6+root 2 is a rational number.. do it by contradiction method​

Answer 1

Answer:

this is the answer of 6+2 root

Step-by-step explanation:

Let 6+root 2 is a rational number then we get that a and b two co-prime integers. Since a and b are two integers. Therefore (6-a/b)is a rational number and So root also is a rational number. But it is contradiction to fact root 2 =(6-a/b) is rational number.