Question

prove that 6 root 3 is an irrational number​

Answer 1

$\pink{\boxed{\green{\underline{\red{\mathrm{Proof:-}}}}}}$

★Let 6√3 be Rational★

→6√3=$\frac{a}{b}$

[a and b are co-prime integers and a,b≠0]

→√3=$\frac{a}{b \times 6}$

→√3=$\frac{a}{6b}$

★Since $\frac{a}{6b}$ is rational, and √3 is Irrational, Which Creates a Contradiction★

=>√3 is irrational

$\rule{200}{1}$

$\mathcal{BE \: BRAINLY}$