Question

prove that 6+root3 is irrational​

Answer 1

Answer:

it is explained down

Step-by-step explanation:

Assume that 6+√3 is rational number

6+√3 = p/q (where p and q are co-primes and 1 is not equal to 0)

√3=p/q-6/1

√3=6q-p/q

here, 6q-p/q is rational number ...but √3 is irrayional

therefore this leads us in contradiction ... and hence 6+√3 is irrational number

Answer 2

Answer:

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