Question

Prove that 6+underroot 2 is an irrational no.

Answer 1

Answer:

Step-by-step explanation:

assume that 6+√2 is a rational no. which can be expressed in the form a/b

6+√2 = a/b

=>√2= a/b-6

=>√2=a-6b/b

=>a-6b/b is rational and hence, √2 is rational

This contradicts the fact that √2 is irrational. Hence our assumption that √2 is a rational no. is thereby wrong.

Therefore, we conclude that 6+√2 is an irrational no.