Question

prove that 7-2√3 is an irrational no.​

Answer 1

Answer:

take root 3 to be rational

therefore , root 3  =  a/b where a and b are co primes and a and b are not equal to zero .

taking b to LHS ,  root 3 b = a

squaring both sides , 3b² = a²

∴ 3 is a factor of a

now a = 3c where c is some integer

squaring

a² = 9c²

3b² =9c²

b²= 3c²

∴ 3 is a factor of b

hence our supposition is wrong

∴ √3 is irrational

we know that rational - irrational = irrational ....

hence proved

PLEASE MARK BRAINLIEST