Math, asked by SripadAdhi, 1 month ago

prove that 7+2√3 is an irrational number​

Answers

Answered by nayanabaraiyaa
0

Step-by-step explanation:

Let assume that 7-2root3 be rational and rational numbers are in the form of p/q form.

\begin{gathered}7 - 2 \sqrt{3} = \frac{p}{q} \\ 7 - \frac{p}{q} = 2 \sqrt{3} \\ \frac{7q - p}{q} = 2 \sqrt{3} \\ \frac{7q - p}{2q} = \sqrt{3} \end{gathered}

7−2

3

=

q

p

7−

q

p

=2

3

q

7q−p

=2

3

2q

7q−p

=

3

We know that root 3 is irrational and not p/q form. It contradicts the statement that it is irrational as it is p/q form.

Subtraction and multiplication of irrational number form irrational number so

7-2root3 is irrational.

Answered by deeparamasastry
0

Answer: = 7+2 = 9 ,

= 9 * √3 cannot be made in to standard form So ,

It is a irrational number AS A RATIONAL NUMBER MUST BE IN THE FORM OF p/q WHERE q ≠0 . And this problem cannot be written like that .

Step-by-step explanation:   Please mark me as the brainliest .

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