Math, asked by karijaswanth5044, 1 year ago

Prove that 7√2/3 is irrational

Answers

Answered by ihrishi
0

Step-by-step explanation:

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Answered by Anonymous
1

Answer:

here we consider

 \sqrt{2}

irrational by theorem

also we r going to use contradiction method

Step-by-step explanation:

let7√2/3 be rational

so it can be written in form

7√2/3 = a (where a is rational)

take 7/3 to other side

a÷7/3 = root2

a×3/7 = root 2

3a/7 = root 2

3a/7 is rational so root 2 should be rational but root 2 is irrational this arises a contradiction because of our incoorect assumption.

therefore 7√2/3 is irrational

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