Prove that 7-2√3 is irrational number
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Answered by
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Answer: by using contradiction method
Step-by-step explanation: consider that 7-2√3 is rational so their must be a fractional form of itna/b
Answered by
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Step-by-step explanation:
Let assume that 7-2root3 be rational and rational numbers are in the form of p/q form.
7 - 2 \sqrt{3} = \frac{p}{q} \\
7 - \frac{p}{q} = 2\sqrt{3} \\
\frac{7q - p}{q} = 2\sqrt{3} \\
\frac{7q - p}{2q} = \sqrt{3} \\
We know that root 3 is irrational and not p/q form. It contradicts the statement that it is irrational as it is p/q form.
Subtraction and multiplication of irrational number form irrational number so
7-2root3 is irrational.
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