prove that 7-2√5 is irrational
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ANSWER ➡️
PROVE THAT 7-2 √5 IS IRRATIONAL NUMBER ➡️
Let us assume 7-2√5 is irrational.
Let 7-2√5 =a/b, where a, b are integers and b≠0.
-2√5=(a/b)-7
» )-2√5=(a-7b) /b
»)√5=(a-7b) /(-2b)
=√5=(7b-a)/2-b
Since a, b integers, (7b-a) /2a is rational, and so √5 is rational.
This contradicts the fact that √5 is irrational.
Hence, 7-2√5 is irrational...
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