Question

Prove that 7-√2 is an irrational number.

Answer 1

Answer:

According to solution √2=r²-57÷28 which means √2 is rational. But it contradicts the fact that √2 is irrational. Hence 7-2√2 is irrational

Answer 2

Step-by-step explanation:

let 7-2 root 2 be a rational number, therefore, 7 -2 root 2 = p/q , where p and q are co-prime numbers. take all the digits to the right hand side till you have only [root 2 ] , that is an irrational number left on the left hand side. therefore, 7- 2 root 2 is an irrational number.

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