prove that 7-2root3 is an irrational number
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Answered by
0
Answer:
Since root 3 is irrational the whole expression becomes irrational.
Step-by-step explanation:
ln short as above because we save time for other answers.
Answered by
2
Proof :
We proof the problem by contradiction.
Without losing generosity, we consider that (7 - 2√3) is a rational number.
Then, 7 - 2√3 = a/b, where both a and b are integers with b ≠ 0
⇒ 2√3 = 7 - a/b
⇒ 2√3 = (7b - a)/b
⇒ √3 = (7b - a)/(2b)
Since a, b are integers, both (7b - a) and 2b are integers, and this implies that √3 is a rational number, which is a contradiction.
∴ (7 - 2√3) is an irrational number.
Hence, proved.
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