prove that 7+3√2 is an irrational no.
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Answered by
28
QUESTION:
prove that 7+3√2 is an irrational no.
ANSWER:
7+3√2
10√2
10×1.414....
14.14....
Therefore, 7+3√2 is an irrational number.
Answered by
1
Answer:
3√ 2 = a/ b -7
= 3√ 2 = ( a-7 b) / b
= √ 2 = ( a - 7b ) / 3b
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