prove that 7+³√2 is an irriational number
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Step-by-step explanation:
Let us assume that ( 7 + 3√2 ) is a rational number
so,
Since,
(p), (q), (7), (3) are integers and q ≠ 0 so,
p - 7q/3q is a rational number
Therefore, √2 is also a rational number which is not possible
√2 is an irrational number
∴ This contradiction arise due to our wrong assumption.
Hence,
7+3√2 cannot be a rational number,
∵ it is an irrational number.
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