prove that 7+ ³√2 is an irriational number
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Step-by-step explanation:
Let us assume,to the contrary,that 7+√2 is rational that is,we can find coprime a and b b=is not equal to o such that 7+√2=a\b therefore, 7+a/b=√2.rearranging this equation,we get √2=7+a/b =7b+a/b since a and b are integers we get 7+a/b is rational,and so √2 is rational but this contradicts the fact that √2 is irrational this contradiction has arisen because of our assume is wrong so the 7+√2is irrational no.
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