prove that √7-3 is an irrational number.
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Let, √7-3 is a rational no. of the form a/b
so,
√7-3 = a/b
√7 = a/ b + 3
√ 7 = a+3b/b
RHS. a+3b is a rational no.
LHS. √ 7 is. a irrational no.
so, RHS IS NOT EQUAL TO RHS.
therefore, √7-3 is an irrational no
so,
√7-3 = a/b
√7 = a/ b + 3
√ 7 = a+3b/b
RHS. a+3b is a rational no.
LHS. √ 7 is. a irrational no.
so, RHS IS NOT EQUAL TO RHS.
therefore, √7-3 is an irrational no
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