Question

Prove that 7+3 root 2 is irrational

Answer 1

yes is it rational number because √2 is rational number.

Answer 2

7
$7 + 3 \sqrt{2 } = p \div q \\ 3 \sqrt{2} = \frac{p - 7q}{q} \\ \sqrt{2} = \frac{p - 7q}{3q}$
p-7q and 3q are integrr but our contradiction is wrong so 7+3root2 is irrational

(BEFORE WE START OUR SOLUTION PLZ LET THE NO. RATIONAL BY CONTRADICTION )