prove that 7√5 is an irrational
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Answer:
yes it is an irrational no. as √5 is an irrational no.
Step-by-step explanation:
Let us assume that 7
5
is rational number
Hence 7 and 5 can be written in the form of p/q
where p,q(q is not equal to zero) are co-prime
7 / 5 = p/q : 5 = (7q)/p
But here
5 is irrational and
(7q)/p
is rational
as Rational is not equal to Irrational
This is a contradiction
so 7√5 is a irrational number.
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