prove that 7√5 is an irrational
Answers
Answered by
1
Answer:
Let us assume that 7√5 is rational number
Hence 7√5 can be written in the form of a/b
where a,b(b is not equal to 0) are co-prime
⟹7√5 = a/b
⟹ √5=a/7b
But here √5 is irrational and a/7b is rational
as Rational is not equal to Irrational .
This is a contradiction
so 7√5 is a irrational number
Similar questions