prove that -7+√5 is an irrational number.
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1
Answer:
Let 7√5 be a rational number.
So,
7√5 = p/q.
(p and q are co-prime number and q ≠ 0)
=> √5 = p/7q
As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.
So, by this we can say that 7√5 is irrational number.
Step-by-step explanation:
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Answer:
Here's a sketch of a proof by contradiction: Suppose √5=pq for some positive integers p and q . ... Then since5 is prime, p must be divisible by 5 too. So p=5m for some positive integer m .
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