Question

Prove that 7√5 is an irrational number​

Answer 1

Answer:

Step-by-step explanation:

Because a, b, and 7 are integers 7b−ab is rational, implying that √5 is rational. But this contradicts with the fact that √5 is irrational. The contradiction is because of the incorrect assumption that 7 - √5 is rational. ∴ We can conclude that 7 - √5 is irrational

Answer 2

Step-by-step explanation:

Opposite sides of a square are both parallel and equal in length. All four angles of a square are equal (each being 360°/4 = 90°, a right angle). All four sides of a square are equal. The diagonals of a square are equal.