Question

prove that 7√5 is irrational​

Answer 1

Step-by-step explanation:

let assume 7√5 as rational

then 7√5=

$7 \sqrt{5 } = \frac{a}{b}$

$\sqrt{5} = \frac{a}{b} \times 7$

$\sqrt{5} = \frac{7a}{b}$

since a and b are integers 7a/b is rational

by equation √5=7a/b

therefore √5 is also rational

but √5 is irrational

so 7√5is irrational

Answer 2

Answer:

7√5 is not a rational number.

Step by step explanation:

We know that the value of √5 is 2.2360.

If is square number we can use the root number of that and we can explain that is a rational number .

Here, 5 is not a square number .

There fore 7√5 is not a rational number.