prove that 7√5 is irrational
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Answered by
5
Answer:
7√5 is irrational.
Step-by-step explanation:
Let us assume that 7√5 is rational number by contradiction
⇒7√5=a/b [∵Where a and b are co-primes and b≠0]
⇒ √5=a/7b
∴Here we can see that R.H.S is a rational that is a/7b but L.H.S is irrational that is √5.
∴Hence our assumption is wrong.
∴7√5 is irrational
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Answered by
4
Explanation
Let us assume , to the contrary , that
7√5 is rational number
Then , there exist co - prime a and b ( b≠0 )
such that
7√5 = a/ b => √5 = a/7b
Since
a and b are integers so a / 7b is rational
Thus
√5 is also rational
But the contradicts
the fact that √5 is irrational. so , our assumption is incorrect
Hence, 7√5 is irrational
Hence proved
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