Math, asked by karuna27678, 7 months ago

prove that 7√5 is irrational​

Answers

Answered by Anonymous
5

Answer:

7√5 is irrational.

Step-by-step explanation:

Let us assume that 7√5 is rational number by contradiction

⇒7√5=a/b [∵Where a and b are co-primes and b≠0]

⇒  √5=a/7b

∴Here we can see that R.H.S is a rational that is a/7b but L.H.S is irrational that is √5.

∴Hence our assumption is wrong.

∴7√5 is irrational

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Answered by Anonymous
4

Explanation

Let us assume , to the contrary , that

7√5 is rational number

Then , there exist co - prime a and b ( b≠0 )

such that

7√5 = a/ b => √5 = a/7b

Since

a and b are integers so a / 7b is rational

Thus

√5 is also rational

But the contradicts

the fact that √5 is irrational. so , our assumption is incorrect

Hence, 7√5 is irrational

Hence proved

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