prove that 7√5 is irrational
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Step-by-step explanation:
Let us assume that 75 is rational number
Hence 75 can be written in the form of ba where a,b(b=0) are co-prime
⟹75=ba
⟹5=7ba
But here 5 is irrational and 7ba is rational
as Rational=Irrational
This is a contradiction
so 75 is a irrational number
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