Question

prove that √7-√5 is irrational number​

Answer 1

Answer:

Let us assume that 7√5 is a rational number

Hence, 7√5 can be written in the form of a/b where a, b are co-prime and b not equal to 0.

7√5 = a/b

√5 = a/7b

here √5 is irrational and a/7b is a rational number.

Rational number ≠ Irrational number

It is a contradiction to our assumption 7√5 is a rational number.

Therefore, 7√5 is an irrational number.

Hence, proved.