Question

Prove that 7-√5 is irrational number
Wrong answer will be reported
And correct answer i will mark as brainlist

Answer 1

Here is your answer:-

Let us assume the contrary that 7 - √5 is rational.

So, we can express 7 - √5 = abab where a and b are co-prime integers and b ≠ 0.

So, √5 = 7 - abab = 7b−ab7b−ab

Because a, b, and 7 are integers 7b−ab7b−ab is rational, implying that √5 is rational.

But this contradicts with the fact that √5 is irrational.

The contradiction is because of the incorrect assumption that 7 - √5 is rational.

∴ We can conclude that 7 - √5 is irrational.

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Answer 2

Answer:

Here is the correct answer answer

Step-by-step explanation:

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