Math, asked by grams1976, 1 month ago

prove that 7√5is irrational​

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Answered by raginikumari37316
0

Answer:

Hence, 7√5 can be written in the form of a/b where a, b are co-prime and b not equal to 0. here √5 is irrational and a/7b is rational number. It is contradiction to our assumption 7√5 is rational number. Therefore, 7√5 is an irrational number.

Answered by krsankar659
0

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