Question

prove that √7 is an irrational number?​

Answer 1

Answer:

Given √7

To prove: √7 is an irrational number.

Proof:

Let us assume that √7 is a rational number.

So it t can be expressed in the form p/q where p,q are co-prime integers and q≠0

√7 = p/q

Here p and q are coprime numbers and q ≠ 0

Solving

√7 = p/q

On squaring both the side we get,

=> 7 = (p/q)2

=> 7q2 = p2……………………………..(1)

p2/7 = q2

So 7 divides p and p and p and q are multiple of 7.

⇒ p = 7m

⇒ p² = 49m² ………………………………..(2)

From equations (1) and (2), we get,

7q² = 49m²

⇒ q² = 7m²

⇒ q² is a multiple of 7

⇒ q is a multiple of 7

Hence, p,q have a common factor 7. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√7 is an irrational number.

Step-by-step explanation:

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Answer 2

Prove that √7 is an irrational number

Answer: Given √7.

To prove: √7 is an irrational number. Proof: Let us assume that √7 is a rational number. So it t can be expressed in the form p/q where p,q are co-prime integers and q≠0. √7 = p/q. ...

Solving. √7 = p/q. On squaring both the side we get, => 7 = (p/q)2 => 7q2 = p2……………………………..(1)