prove that√7 is irrational
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Hi friend, Here's the required answer:-
Let us assume that 2/√7 is rational number.
2/√7= 2/√7 × (√7/√7)= 2√7/7. ( Rationalising)
Now, 2√7/7 = p/q ( as rational no. can be written in the form of p/q=)
2√7= 7p/q
√7= 7p/2q
Here LHS is irrational but RHS is rational.
This contradicts the statement.
Our assumption is wrong.
2/ √7 is an irrational number.
Hope this helps you...
All the best….
Let us assume that 2/√7 is rational number.
2/√7= 2/√7 × (√7/√7)= 2√7/7. ( Rationalising)
Now, 2√7/7 = p/q ( as rational no. can be written in the form of p/q=)
2√7= 7p/q
√7= 7p/2q
Here LHS is irrational but RHS is rational.
This contradicts the statement.
Our assumption is wrong.
2/ √7 is an irrational number.
Hope this helps you...
All the best….
Answered by
0
do long division of
and if the ans is non terminating and repeating it is irrational
and if the ans is non terminating and repeating it is irrational
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