Question

prove that 7 over root 3 is irrational number ​

Answer 1

Answer:

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Step-by-step explanation:

$7\sqrt[]{3}$ is an irrational number as neither 7 nor $\sqrt{3}$ can be simplified any further

Answer 2

Answer:

7√3 is an irrational number

Step-by-step explanation:

assume 7√3=a\b

√3=a+7b/b

LHS=irrational. RHS=rational

therefore 7√3 is an irrational number

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