prove that 7 root 3 + root 5 is irrational
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Step-by-step explanation:
assume that 7√3+√5 is rational
so let x= 7√3+√5 for a rational no. x
=in x=7√3+√5,both side are rational as assumed
= now, x= 7√3+√5
=7√3=√5+x ( by exchanging)
= √3=√5+x /7
here, as both side of x = 7√3+√5 are rational,then RHS should be √3= (√5+x)/7.
But this contradicts our earlier assumption that 7√3+√5 is rational, because the RHS of √3=√5+x/7 is rational. While the LHS is irrational.
Hence proven
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