Question

prove that 7 root 5 is irrational ​

Answer 1

Answer:

$\huge \orange{\underline {Hey\: MATE}}$

$\huge \red {\mathbb { ANSWER}}$

Step-by-step explanation:

$to \: prove \: that \: 7 \sqrt{5} \: is \: an \ \\ : irrational \\ \\proof \: \: \\ let \: the \: 7 \sqrt{5} \: is \: rational \\ then.there \: exist \: co - primes \\ a \: and \: b \: (b \: not \: equal \: to \: \: 0 \\ such \: that \\ 7 \sqrt{5} = \frac{a}{b } \\ \sqrt{7} = \frac{a}{7b} \\ since \: a \: and \: b \: is \: integer \\ so \: \: \frac{a}{7b } is \: rational \:$

thus, √5 is also rational.

But, this contradicts the fact that √5 is irrational. so our assumption is incorrect.

Hence ,7√5 is irrational.

Thank you

Answer 2

Answer:

hi friend

Step-by-step explanation:

here is your question to answer

I hope you understand