Question

-prove that 7 root 5
is
sectional
​

Answer 1

Answer:

Step-by-step explanation:

7√5 is irrational

Suppose that 7√5is rational no.

7√5=a/b(where a and b are coprime and b is not equal to 0)

7√5*a/b

√5=a/b-7

√5=a-7b/b

We know that a-7b/b is rational no. And √5is irrational no.

So this contradication and supposition is wrong 7√5is irrational no.

HENCE PROVED

Answer 2

Answer:assume root7 is a rational

a and b is not equal to 0

root 7=a/b

root 7×b=a

squaring on both side

7b square=a square

a = 7c for some integer c

Substituting for a we get 7b square= 49c square

This means b square is divisible by 7 and b is also divisible by 7

a and b are corrine no

Our assumption is wrong root 7 is a irrational no

Step-by-step explanation: