Prove that 8-((2×under root7)/3) is an irrational number
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hey mate..here is your answer..⬇️⬇️⬇️⬇️⬇️⬇️⬇️
let 8-2√7/3 be a rational number and is of the form if p/q where p and q are some integers and qis no equal to 0
so 8-2√7/3 =p/q
=> 8-2√7= 3p/q
=> 8-(3p/q)=2√7
=> 8q-3p/q= 2√7
=> 8q-3p/2q=√7
here 8q ,3p and 2q are intergers
so, 8q-3p/2q is a rational number
but √7 is an irrational number
so our assumption is wrong
=> 8-2√7/3 is an irrational number
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