Math, asked by ilayacheliyan733, 9 months ago

Prove that 8-√2is irrational number

Answers

Answered by Sudhir1188
1

ANSWER:

  • (8-√2) is an irrational number.

GIVEN:

  • Number = 8-√2

TO PROVE:

  • 8-√2 is an Irrational number.

SOLUTION:

 \implies \: 8 -  \sqrt{2}  =  \dfrac{p}{q}  \\  \\  \implies \: 8 -  \dfrac{p}{q}  =  \sqrt{2}  \\  \\  \implies \:  \ \dfrac{8q - p}{q}  =  \sqrt{2}

Here:

  • (8q-p)/q is rational but √2 is Irrational.
  • Thus our contradiction is wrong.
  • (8-√2) is an irrational number.

NOTE:

  • This method of proving and irrational number is called contradiction method.
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