Math, asked by akku4363, 9 months ago

Prove that √8+5 is irrational​

Answers

Answered by rio123491
17

Step-by-step explanation:

lets assume that

 \sqrt{8}  + 5

is a rational no.

therefore it can be represented in the p/q form where p and q are co-primes

  \sqrt{8}  + 5 =  \frac{x}{y} \\  \sqrt{8}  =  \frac{x - 5y}{y}

here

 \sqrt{8}  \: is \: not \: a \: rational \: no. \: but \:  \frac{x - 5y}{y} \:  is  \: a \: rational \: no.

therefore our assumption was wrong

therefore

 \sqrt{8}  + 5 \: is \: an \: irrational \: no.

Answered by skvijay36
11

Answer:

Step-by-step explanation:

let us assume root8+5is rational number

if root8+5 is rational it is in the form of p/q

q is not equal to zero where p and q are integers.

root8+5=a/b [where a and b are co-primes]

5/1-a/b=root8

5(b)-a(1)/b= root 8  [LCM]

5b-a/b=root8

in 5b-a/b ,a and b are integers so it is rational number

but this contradicts are fact that root 8 is irrational (root p is irrational )

there fore root 8+5 is irrational number

hence proved  

hope it is use full

thank you

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