Prove that 8-√7 is an irrational number
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Answer with Step-by-step explanation:
Let us assume that 8 -√7 is a rational number.
So it t can be expressed in the form p/q where p,q are co-prime integers and q≠0
8 - √7 = p/q
Here p and q are coprime numbers and q ≠ 8 - √7 = p/q
On squaring both the side we get,
⇒ 57 = (p/q)²
⇒ 57 q² = p² ..(1)
p²/57 = q²
So, 57 divides p and q but, p and q are multiple of 57.
⇒ p = 57m
⇒ p² = 3249m² ..(2)
From equations (1) and (2), we get,
57q² = 3249m²
⇒ q² = 57m²
⇒ q² is a multiple of 57
⇒ q is a multiple of 57
∴ p, q have a common factor 57. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number
8 - √7 is an irrational number.
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