Prove that 8,8√3,16 forms a right angled triangle
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by Pythagoras theorem,
h^2= b^2 + p^2
16^2= 8^2 + (8root3)^2
256 = 64 + (8*8*root3*root3)
256 = 64 + 192
256 = 256
h^2= b^2 + p^2
16^2= 8^2 + (8root3)^2
256 = 64 + (8*8*root3*root3)
256 = 64 + 192
256 = 256
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