Math, asked by sonamydv097, 1 month ago

prove that 8 - root 2 is irrational no.​

Answers

Answered by sumita78debnath
0

Answer:

8-v/2

2^(3-1/2)

2^(5/2)

WHICH IS AN IRRATIONAL NO

Answered by Itzsidhu193
71

{\boxed{\sf{Solution:-\:}}}

\sf\underline{To\: prove:-\:}

 \sf8 -  \sqrt{2}

 \sf \: Let \:   8 -   \sqrt{2}    \: be  \: a \: \\ rational \:  number \:  which \:  can \:  be \\ \:  expressed \:  in  \: the  \: form \:  of \:  \\ \frac{p}{q}  \:  where \:  p \:  and \:  q \: \\ have \:  no \:  other  \: common \:  factor \: \\ than \:  1 \\ \:  \frac{8q - p}{q}   \: is \: \\ rational \:  but \:  √2 \:  is \:  Irrational \: .

\huge\fbox\pink{Hence , \: its\: proved\:}

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