Question

Prove that 8n never ends with digit 0

Answer 1

For a number to end with the digit 0 it's prime factorization should have 2 and 5 as a common factor.

here 8^n = (2*4)^n doesn't have 5 in its prime factorization.

Therefore 8^n cannot end with the digit 0.

Hope this helps!

Answer 2

Factors of 8n = 2x2x2

And we know that the digits which have factor 5 and 2 only can ends with 0.
But factors of 8 is only 2
So it can't be ends with 0.
Hope it'll help u...