prove that 9-2√2 is irrational
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Answered by
1
Answer:
Step-by-step explanation:
9-2√2=a/b
-√2= a-9/2b
Since a-9/2bis rational
We know that √2 is irrational
So 9-2√2 is irrational
Answered by
0
Step-by-step explanation:
Let us assume that 9-2√2 is rational
let,9-2√2=a/b(such that a and b are coprime)
9-2√2=a/b
-2√2=a/b-9
2√2=9-a/b
2√2=9b-a
√2=9b-a/2b(where a and b are integers)
since 9b-a/2b is rational therefore .√2is rational
But it contradicts the fact that √2 is irrational
This contradiction has arisen due to our incorrect assumption that 9-2√2 is rational
Thus we conclude that 9-2√2 is irrational
MARK IT AS BRAINLIEST PLEASE
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